Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.

Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.

This December represents the 50th anniversary of the historic connection between Roger Staubach and Drew Pearson.

Type 1 diabetes (also known as diabetes mellitus) is an autoimmune disease in which immune cells attack and destroy the insulin-producing cells of the pancreas. The loss of insulin leads to the ...

To be eligible for JEE Advanced 2026, candidates must rank among the top 2.5 lakh students in JEE Main 2026, satisfy the age criteria. Additionally, candidates must have appeared for their Class 12 ...