SOLVED: A computer has 8 GB of memory with 64-bit word sizes. Each block of memory stores 16 words. The computer has a direct-mapped cache of 128 blocks. The computer uses word-level addressing, which means that the offset refers to individual words (not bytes) in the block.a) What is the address format? Give the total number of bits needed and how the bits are distributed between the tag, index (which block), and offset. If we change the cache to a 4-way set associative cache, what would be the

In a direct-mapped cache, each memory block can be placed in ex... | Filo

SOLVED:For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. What is the cache block size (in words)? How many entries does the cache have? What is the ratio between total bits required for such a cache implementation over the data storage bits? Starting from power on, the following byte-addressed cache references are recorded. Address 0 4 16 132 232 160 1024 30 140 3100 180